Q. 3. Compute the approximate value of the integral (June 2001)
I =(x + x2) dx
using Simpson's rule by taking interval size h as 1.

Solution.

x -1 0
1
y = (x + x2) 0 0
2

Here, h = 1, y0 = 0, y1 = 0, y2 = 2
y dx = (1/3) X [(0 + 2) + (4 X 0)]
ory dx = 2/3

Q. 4. Compute the approximate value of the integral (Dec. 2000)
I =[1/(1 + x2)] dx
using Simpson's rule by taking interval size h as 1.

Solution.

x 0 1
2
3
4
5
6
y = [1/(1 + x2)] 1 0.5
0.2
0.1
0.058
0.038
0.027

y dx = (1/3) X {(1 + 0.027) + [4 X (0.5 + 0.1 + 0.038)] + [2 X (0.2 + 0.058)]}
or y dx = 1.36



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